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14(导学案1)第4单元综合实力评价

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一、直接写出得数。
<Object: word/embeddings/oleObject1.bin>÷3=              <Object: word/embeddings/oleObject2.bin>×2=             <Object: word/embeddings/oleObject3.bin>÷3=              3÷<Object: word/embeddings/oleObject4.bin>=
<Object: word/embeddings/oleObject5.bin>×<Object: word/embeddings/oleObject6.bin>=            <Object: word/embeddings/oleObject7.bin><Object: word/embeddings/oleObject8.bin>=            10×<Object: word/embeddings/oleObject9.bin>=             <Object: word/embeddings/oleObject10.bin>+<Object: word/embeddings/oleObject11.bin>=
<Object: word/embeddings/oleObject12.bin>÷<Object: word/embeddings/oleObject13.bin>=            <Object: word/embeddings/oleObject14.bin>÷<Object: word/embeddings/oleObject15.bin>=           <Object: word/embeddings/oleObject16.bin>÷<Object: word/embeddings/oleObject17.bin>=           <Object: word/embeddings/oleObject18.bin>÷<Object: word/embeddings/oleObject19.bin>=
二、填空。
1、40的<Object: word/embeddings/oleObject20.bin>是(        )。     2、一个数的<Object: word/embeddings/oleObject21.bin>是25,这个数是(         )。
3、45分=(       )时                20分=(        )时
   60千克=(        )吨             32分=(        )元
4、<Object: word/embeddings/oleObject22.bin>=(      )÷(      )=(      )︰(      )=(      )(填小数)
5、一批货物的<Object: word/embeddings/oleObject23.bin>是180吨,这批货物有(      )吨。
6、已知a×<Object: word/embeddings/oleObject24.bin>=<Object: word/embeddings/oleObject25.bin>×b=c×<Object: word/embeddings/oleObject26.bin>,并且a、b、c都不等于0.那么,a、b、c按从小到大的顺序排列是(                )。
7、有2吨货物,甲车每次运<Object: word/embeddings/oleObject27.bin>,乙车每次运<Object: word/embeddings/oleObject28.bin>吨。若单独运完这些货物,甲车需运(     )次,乙车需运(      )次。
三、计算下面各题。
<Object: word/embeddings/oleObject29.bin>÷[8×(<Object: word/embeddings/oleObject30.bin><Object: word/embeddings/oleObject31.bin>)]            [1-(<Object: word/embeddings/oleObject32.bin>+<Object: word/embeddings/oleObject33.bin>)]÷<Object: word/embeddings/oleObject34.bin>        

四、下面各题怎样算简便就怎样算。
<Object: word/embeddings/oleObject35.bin><Object: word/embeddings/oleObject36.bin>)×<Object: word/embeddings/oleObject37.bin>         (<Object: word/embeddings/oleObject38.bin>+<Object: word/embeddings/oleObject39.bin>)÷<Object: word/embeddings/oleObject40.bin>         <Object: word/embeddings/oleObject41.bin>×<Object: word/embeddings/oleObject42.bin><Object: word/embeddings/oleObject43.bin>÷11
五、选择。(把正确答案的序号填在括号里)
1、电扇厂原计划生产电扇100万台,现在生产了120万台,增产了几分之几?
列式是(     )。
A.120÷100-1  B.1-100÷12  C.(120-100) ÷120  D.(120-100) ÷100
2、一根绳子长4米,比另一根短<Object: word/embeddings/oleObject44.bin>米,另一根绳子长(      )。
A.<Object: word/embeddings/oleObject45.bin>米           B.<Object: word/embeddings/oleObject46.bin>米            C.3米             D.<Object: word/embeddings/oleObject47.bin>
六、解方程。
<Object: word/embeddings/oleObject48.bin>x-2=<Object: word/embeddings/oleObject49.bin>       x÷<Object: word/embeddings/oleObject50.bin>=<Object: word/embeddings/oleObject51.bin>      <Object: word/embeddings/oleObject52.bin>+<Object: word/embeddings/oleObject53.bin>x=<Object: word/embeddings/oleObject54.bin>        <Object: word/embeddings/oleObject55.bin>x-<Object: word/embeddings/oleObject56.bin>x=10
七、解决实际问题。
1、一根电线杆全长的<Object: word/embeddings/oleObject57.bin>是2米,这根电线杆全长多少米?露出地面的部分占全长的<Object: word/embeddings/oleObject58.bin>,露出地面的部分是几米?
2、某乡去年绿色蔬菜的总产量比今年少<Object: word/embeddings/oleObject59.bin>,去年比今年少110吨,今年的产量是多少吨?
一个长方体,从同一顶点引出的3条棱共长24厘米,这个长方体的长、宽、高的比是
5︰4︰3,这个长方体的长、宽、高各是多少?
6、学校新购进了一些球,新购进的足球占购球总数的<Object: word/embeddings/oleObject60.bin>,新购进的足球有60个,学校新购进了多少个球?(用算术和方程两种方法解答)
★、甲、乙两汽车从A、B两地相向而行,相遇时所行路程比是5︰3,这时乙车距两地的中点还有80千米,求两地相距多少千米?
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